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Numerical Ability: Formula & Concept Reference

Every major Numerical Ability formula, each with a real worked example. Use this alongside practice questions — seeing the formula, then applying it, is how it actually sticks.

1. Number Problem

"A less than B" means → B − A

"A more than B" means → B + A

Digit problems

abc = 100a + 10b + c

sum of digits = a + b + c

Worked example — Word-rule example

A number is 8 less than twice another number. Their sum is 40. Find the numbers.

Explanation: "X less than Y" = Y − X, so the number = 2(other number) − 8.

  • x = 2y − 8
  • x + y = 40
  • (2y − 8) + y = 40 → 3y = 48

Answer: y = 16, x = 24

Check: 2(16) − 8 = 24 ✓, and 24 + 16 = 40 ✓

Worked example — Two-digit example

The sum of the digits of a two-digit number is 12. When the digits are reversed, the new number is 18 less than the original. Find the number.

Explanation: Let a = tens digit, b = units digit. Original = 10a + b, reversed = 10b + a.

  • a + b = 12
  • 10b + a = (10a + b) − 18 → a − b = 2

Answer: a = 7, b = 5, number = 75

Check: reversed = 57, and 75 − 57 = 18 ✓

Worked example — Three-digit example

In a three-digit number, the hundreds digit is twice the units digit, and the tens digit is 3 more than the units digit. The sum of the digits is 11. Find the number.

Explanation: Let c = units digit. Then a = 2c and b = c + 3.

  • a + b + c = 11 → 2c + (c + 3) + c = 11 → 4c = 8

Answer: c = 2, a = 4, b = 5, number = 452

Check: 4 + 5 + 2 = 11 ✓

2. Money Problem

P = SP − C

Discount

NSP = SP(1 − D)

NP = NSP − C

Raise

NSP = SP(1 + R)

NP = NSP − C

  • P = profit
  • SP = selling price
  • C = cost
  • NSP = new selling price
  • NP = new profit
  • D = discount
  • R = raise

Worked example — Discount

A boutique owner spends ₱450 to produce a dress and sets the original selling price at ₱750. During a flash sale, she offers a 20% discount. Find the new selling price and new profit.

  • NSP = 750(1 − 0.20) = ₱600
  • NP = 600 − 450 = ₱150

Answer: ₱150

Check: original profit was 750 − 450 = ₱300, so the discount cut profit in half

Worked example — Raise

A hardware store buys a tool for ₱200 and originally sells it for ₱280. The owner raises the price by 15%. Find the new selling price and new profit.

  • NSP = 280(1 + 0.15) = ₱322
  • NP = 322 − 200 = ₱122

Answer: ₱122

Check: original profit was 280 − 200 = ₱80, so the raise added ₱42

3. Motion Problem

Object to object relationship

same direction → subtract

opposite direction → add

Object to environment relationship

same direction → add

opposite direction → subtract

Worked example — Object to object — chase problem

Train A is 150 km ahead of Train B on the same track, both moving in the same direction. Train B travels at 90 km/h, Train A at 60 km/h. How long will it take Train B to catch up?

Explanation: Same direction → subtract the speeds to get relative speed. Train B must be the faster one to actually close the gap.

  • relative speed = 90 − 60 = 30 km/h
  • time = 150 ÷ 30

Answer: 5 hours

Worked example — Object to environment — river current

A boat's speed in still water is 20 km/h, on a river with a 5 km/h current. Find downstream and upstream speed, then the total time for a 60 km round trip.

Explanation: Same direction (downstream) → add. Opposite direction (upstream) → subtract.

  • downstream = 20 + 5 = 25 km/h → time = 60 ÷ 25 = 2.4 h
  • upstream = 20 − 5 = 15 km/h → time = 60 ÷ 15 = 4 h

Answer: 6.4 hours total

4. Age Problem

Past (m)PresentFuture (n)
Boyx − mxx + n
Girly − myy + n

Worked example — Past to present

Six years ago, a father was four times as old as his son. If the father is now 34, how old is the son now?

Explanation: x = father's present age = 34. Past column: x − m and y − m, with m = 6.

  • x − 6 = 4(y − 6)
  • 28 = 4y − 24 → 4y = 52

Answer: y = 13

Check: 6 years ago: father 28, son 7, and 28 = 4 × 7 ✓

Worked example — Present to future

A mother is currently three times as old as her daughter. In 10 years, she will be twice as old as her daughter. Find their present ages.

Explanation: Present: x = 3y. Future column with n = 10: x + n = 2(y + n).

  • 3y + 10 = 2(y + 10)
  • 3y + 10 = 2y + 20

Answer: y = 10, x = 30

Check: in 10 years: mother 40, daughter 20, and 40 = 2 × 20 ✓

5. Percentage Problem

Think of percentage problems as:

PART = RATE × WHOLE (P = R × B)

  • P = Part
  • R = Rate (decimal)
  • B = Base / Whole

Worked example — Solving for Part

A store has 240 items in stock. If 35% are sold in one day, how many are sold?

  • P = 0.35 × 240

Answer: 84 items

Worked example — Solving for Base

45 students represent 15% of all students in a school. How many students in total?

  • 45 = 0.15 × B
  • B = 45 ÷ 0.15

Answer: 300 students

Worked example — Solving for Rate

Out of 60 questions, a student answered 18 correctly. What percent is that?

  • 18 = R × 60
  • R = 18 ÷ 60 = 0.30

Answer: 30%

6. Work Problem

Rate = Work output ÷ time

Workers have different rate

1/A + 1/B = 1/t

Workers have the same rate

Use the concept of manpower (man-days, man-hours) to represent the plan and the done.

Plan = Done

Rate = Work output ÷ (Plan / Done)

Worked example — Different rate

Pedro can paint a fence alone in 6 hours, Juan in 4 hours. Working together, how long will it take?

  • 1/6 + 1/4 = 1/t
  • 2/12 + 3/12 = 5/12 = 1/t

Answer: t = 12/5 = 2.4 hours

Worked example — Same rate (manpower)

It takes 8 workers 10 days to build a wall. How many days for 5 workers at the same rate?

  • Plan = 8 × 10 = 80 man-days
  • Done = 5 × d
  • 80 = 5d

Answer: 16 days

7. Interest Problem

Simple interest

I = P × r × t

Compound interest

A = P(1 + r)n

Interest = A − P

  • P = principal (starting amount)
  • r = annual interest rate, as a decimal
  • t = time in years
  • n = number of years (compound interest)
  • A = final amount
  • I = interest earned

Worked example — Simple interest

₱50,000 is invested at 9% simple annual interest. How much total interest is earned after 2 years and 6 months?

  • I = 50,000 × 0.09 × 2.5

Answer: ₱11,250

Worked example — Compound interest

₱40,000 is invested at 8% annual interest, compounded annually, for 2 years. What is the total amount after 2 years?

  • A = 40,000 × (1.08)²
  • A = 40,000 × 1.1664

Answer: ₱46,656

Check: interest earned = 46,656 − 40,000 = ₱6,656

8. Fractions Cheat Sheet

Additiona/b + c/d = (ad+bc)/bd
Subtractiona/b − c/d = (ad−bc)/bd
Multiplicationa/b × c/d = ac/bd
Divisiona/b ÷ c/d = a/b × d/c
LCDLCM of denominators
LCD (2 numbers)(a×b) / GCF

Worked example

2/3 + 1/4

  • (2×4 + 1×3) / (3×4) = (8+3)/12

Answer: 11/12

Worked example

3/5 − 1/4

  • (3×4 − 1×5) / (5×4) = (12−5)/20

Answer: 7/20

Worked example

2/5 × 3/7

  • (2×3)/(5×7)

Answer: 6/35

Worked example

3/4 ÷ 2/9

  • 3/4 × 9/2 = (3×9)/(4×2)

Answer: 27/8

Worked example

LCD of 4, 6, 9

  • 4=2², 6=2×3, 9=3² → take highest powers: 2²×3²

Answer: 36

Worked example — two-number formula

LCD of 6 and 8

  • GCF(6,8) = 2
  • (6×8) ÷ 2

Answer: 24

Check: multiples of 6: 6,12,18,24... multiples of 8: 8,16,24... first common = 24 ✓

9. Ratio and Proportion

Ratioa : b = a/b
Proportiona/b = c/d
Cross multiplicationad = bc
Direct proportiona/b = c/d
Inverse proportionab = cd
Ratio sharing(part/total ratio) × total

Worked example — Ratio

3 cups flour to 2 cups sugar, as a ratio.

Answer: 3:2 = 3/2

Worked example — Proportion → cross multiplication

Boys to girls is 3:5. There are 12 boys — how many girls?

  • 3/5 = 12/g
  • 3g = 5 × 12 = 60

Answer: g = 20

Worked example — Direct proportion

A car travels 150 km in 3 hours at constant speed. How far in 5 hours?

  • 150/3 = x/5
  • 3x = 750

Answer: 250 km

Worked example — Inverse proportion

4 workers build a wall in 12 days. How many days for 6 workers, same rate?

  • 4 × 12 = 6 × d
  • 48 = 6d

Answer: 8 days

Worked example — Ratio sharing

₱4,500 split between two siblings in ratio 2:3.

  • total ratio = 5
  • first: (2/5)×4500 = 1800
  • second: (3/5)×4500 = 2700

Answer: ₱1,800 and ₱2,700

Check: 1800 + 2700 = 4500 ✓

10. Basic Arithmetic — What to Memorize

Additiona + b
Subtractiona − b
Multiplicationa × b
Divisiona ÷ b
OrderPEMDAS
AverageSum ÷ Number of values
Fraction additionFind LCD first
Fraction multiplicationMultiply across
Fraction divisionKeep, Change, Flip
Same signsPositive when multiplying/dividing
Different signsNegative when multiplying/dividing

Worked example — Addition

47 + 68

Answer: 115

Worked example — Subtraction

152 − 87

Answer: 65

Worked example — Multiplication

23 × 14

Answer: 322

Worked example — Division

144 ÷ 12

Answer: 12

Worked example — Order (PEMDAS)

6 + 2 × (5 − 3)² ÷ 4

Explanation: Parentheses, then Exponents, then Multiplication/Division left to right, then Addition/Subtraction left to right.

  • (5−3) = 2 → 2² = 4
  • 2 × 4 = 8 → 8 ÷ 4 = 2
  • 6 + 2

Answer: 8

Worked example — Average

Find the average of 12, 18, 25, 9, and 16.

  • Sum = 12+18+25+9+16 = 80
  • Number of values = 5

Answer: 80 ÷ 5 = 16

Worked example — Fraction addition

5/6 + 1/4

Explanation: Find the LCD first — LCD(6,4) = 12.

  • 10/12 + 3/12

Answer: 13/12 = 1 1/12

Worked example — Fraction multiplication

3/8 × 4/9

Explanation: Multiply across — numerators together, denominators together.

  • (3×4)/(8×9) = 12/72

Answer: 1/6

Worked example — Fraction division

5/6 ÷ 2/3

Explanation: Keep the first fraction, Change ÷ to ×, Flip the second fraction.

  • 5/6 × 3/2 = 15/12

Answer: 5/4 (or 1 1/4)

Worked example — Same signs

(−8) × (−5)

Explanation: Multiplying two numbers with the same sign gives a positive result.

Answer: 40

Worked example — Different signs

(−8) × 5

Explanation: Multiplying two numbers with different signs gives a negative result.

Answer: −40

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